What does your Jython implementation of IJavaInterface look like? My 
guess is that you left off the 'self' argument to login(); i.e. in you 
.py file you should have something like this:

import IJavaInterface

class MyInterface(IJavaInterface):
     def login(self):
         pass

Member functions should always have at least one argument - self. If you 
omit the 'self' argument that will cause the error you are getting.

Kent


Stephane Blardone wrote:
>   
>  
>  I’m trying to use an instance of a java interface ( the interface is 
>  implemented in jython) in a java program.
>  
>   
>  
>  Using the __tojava__ method I get a ‘java instance’ of the jython object 
>  but when I try to call a method of the
>  
>  interface from java I get a “TypeError: login() too many arguments; 
>  expected 0 got 1”
>  
>   
>  
>  here’s the code I use.
>  
>   
>  
>        IJavaInterface myJythonObject = null;
>  
>   
>  
>        PythonInterpreter tInterp = new PythonInterpreter();
>  
>        Properties tPythonProperties = new Properties();
>  
>        tPythonProperties.setProperty("python.path", “c:/share/lib" );
>  
>        PythonInterpreter.initialize(System.getProperties(), 
>  tPythonProperties, null);
>  
>       
>  
>        try {
>  
>             
>  
>              File tFile = new File("c:/temp/test.py ");
>  
>              FileInputStream tFileStream = new FileInputStream(tFile);
>  
>              try {
>  
>   
>  
>                          tInterp.setErr(System.out);
>  
>                          tInterp.execfile(tFileStream);
>  
>                          tInterp.exec("x=TestClass()");
>  
>                          PyObject pObj1 = tInterp.get("x");
>  
>                          myJythonObject = 
>  (IjavaInterface)pObj1.__tojava__( IjavaInterface.class);
>  
>                         
>  
>                          myJythonObject.login();    ß-------this throws a 
>  TypeError: too many arguments
>  
>              }
>  
>              catch(Exception tEx) {
>  
>                          System.out.println(tEx.toString());
>  
>              }
>  
>        }
>  
>   
>  
>  I have looked at previous postings on jython-user and googled the 
>  problem but I have not found a solution
>  
>  I’m a jython newb so I probably either missed something or made some 
>  incorrect assumptions.
>  
>  Should I not be using the myJythonObject like it is a java object?
>  
>  I can use __findattr__(“login”) and use the __call__ method but this 
>  would defeat the purpose of the interface.
>  
>   
>  
>  Any help would be greatly appreciated.
>  
>   
>  
>  -stephane
>  
>   
>  


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