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MyASPN >> Mail Archive >> boost
boost
Re: [boost] API Review request: XML API for C++, second round
by Hamish Mackenzie other posts by this author
Jun 26 2003 8:00PM messages near this date
Re: [boost] API Review request: XML API for C++, second round | Re: [boost] API Review request: XML API for C++, second round
On Thu, 2003-06-26 at 19:51, Stefan Seefeld wrote:
>  Hamish Mackenzie wrote:
>  
>  >>>>And I don't use a 'document' class, as that is managed implicitely
>  >>>>by my dom::document_ptr:
>  >>>>
>  >>>>dom::document_ptr document; // create new document;
>  >>>>dom::document_ptr doc(document); // create second reference to it
>  >>>>dom::document_ptr doc2 = document.clone(); // clone it, i.e. make deep
>  >>>>                                              copy
>  >>>
>  >>>
>  >>>This is not consistent with the standard library or C++ in general.  It
>  >>>will seem strange that the pointer class
>  >>>1) Does not require dereferencing
>  >>
>  >>would you say the same if the class name was spelled 'document_ref'
>  >>instead ?
>  > 
>  > 
>  > 1 & 4 would be ok, but 3 would stand and having an 'operator bool' would
>  > be added to the list.
>  > 
>  > 
>  >>>3) Has a constructor such as document_ptr( "config.xml" )
>  >>>4) Has member functions such as write_to_file
>  >>>
>  >>>The alternative would allow both...
>  >>>
>  >>>boost::shared_ptr< dom::document > doc( new dom::document() );
>  >>>boost::shared_ptr< dom::document > doc1( doc );
>  >>>dom::document doc2( *doc1 );
>  >>>
>  >>>and if the 'doc1' reference was non-owning...
>  >>>
>  >>>dom::document doc();  // Create new doc
>  >>>dom::document & doc1( doc ); // Second reference
>  >>>dom::document doc2( doc1 );  // Deep copy
>  >>
>  >>right, but given such an approach, what would nodes return in their
>  >>'parent()' method ?
>  > 
>  > 
>  > The parent is always an element (is that right?) so it would return
>  > element_ptr or element_ref.
>  
>  yes. Sorry, I meant to ask what 'document()' would return.

Assuming xmlNode::doc cannot be null it would return document_ref.

You might be worried about...

dom::document dom;
assert( &dom.root().document() == &dom );

I think this can work be made to work with

bool operator ==( document * p1, document_ref * p2 )
{
  return p1-> raw_ == p2->raw_;
}

bool operator ==( document_ref * p1, document * p2 )
{
  return p1-> raw_ == p2->raw_;
}

etc.

-- 
Hamish Mackenzie <hamish@[...].uk> 

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