Re: [C++-sig] Static, again...
by David Abrahams other posts by this author
Nov 12 2002 7:55PM messages near this date
Re: [C++-sig] Re: Static, again...
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Re: [C++-sig] Static, again...
Hugo van der Merwe <hugo@[...].za> writes:
> I had a look at the mailing list archives about this topic, I'm still
> not clear on how exactly it works:
>
> > #include <boost/python/module.hpp>
> > #include <boost/python/class.hpp>
> >
> > struct Num {
> > Num() {}
> > ~Num() {}
> > static int getDims() {return 3;}
> > int dims() {return 5;}
> > };
> >
> > BOOST_PYTHON_MODULE_INIT(numTest)
> > {
> > using namespace boost::python;
> > module numTestMod("numTest");
> > numTestMod
> > .add
> > ( class_<Num>("Num")
> > .def_init()
> > .def("getDims",&Num::getDims)
> > .def("dims", &Num::dims)
> > )
> > ;
> > }
>
> > We don't have a way to make true static methods yet.
This part is still true.
> > getDims will work fine if you access it through the class like this:
> >
> > Nums.getDims()
I was wrong when I posted that.
> I am trying to wrap a "Settings" class which does not have a public
> constructor, it expects you to call "GetInstance" to get a pointer to
> the always-existing instance (making the settings "global"). The above
> would make me think that this will work:
>
> class_<Settings, boost::noncopyable>("Settings", no_init)
> .def("GetInstance", &Settings::GetInstance,
> return_value_policy<reference_existing_object>());
>
> I cannot call Settings.GetInstance(), it gives me:
>
> TypeError: unbound method Boost.Python.function object must be called with Settings instan
ce as first argument (got nothing instead)
Right, that won't work.
> I also read about an approach that looks something like this:
>
> object settings_class =
> class_<Settings, boost::noncopyable>("Settings", no_init);
> settings_class.attr("Settings") = &Settings::GetInstance;
>
> But I don't know how that is supposed to work...
Yeah, that won't work either.
> If I wanted to expose GetInstance as Settings() instead (once I get it
> working), is it as simple as just calling it "__init__" instead?
Unfortunately, no. That would be cool, though, wouldn't it? I'm
pretty sure you can do this after you define class_<Settings> , though:
// Note no leading dot.
def("Settings", &Settings::GetInstance
, return_value_policy<reference_existing_object> ());
This will replace the class in the module by a function called
Settings that gets the instance.
> (Should I then have no_init in the class_<> invocation or not?
Yep.
> I noticed the tutorial talks about no_init, but then mentions as
> soon as you wish to derive classes from it, you do not want
> no_init. So when is no_init useful? Only when you cannot construct a
> class and don't want to derive from it, i.e. when you're using
> "factories"?)
I think that's right. However, I wonder if we should change the
__init__ function that you get from no_init to be a no-op unless the
Python class actually has the same type as the abstract base...
> I am really astonished with what can be achieved with C++ -
> Boost.Python is really amazing!
Thank you!
--
David Abrahams
dave@[...].com * http://www.boost-consulting.com
Boost support, enhancements, training, and commercial distribution
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Hugo van der Merwe
Scott A. Smith
David Abrahams
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David Abrahams
David Abrahams
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Hugo van der Merwe
David Abrahams
Hugo van der Merwe
David Abrahams
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