Joel Gerard <llywelyn.geo@[...].com>  writes:

>  Thanks for the advice. There are a few things I'm still vague on though. I've been overloa
ding
>  static, and non-static members without apparent problems, but I'm now starting to be suspi
cious. 
> 
>  For instance, I have: 
> 
>  Vector (Vector::*CreateCross1)(const Vector&) const  = &Vector::CreateCross ;
>  Vector (*CreateCross2)(const Vector&, const Vector&) = &Vector::CreateCross; 
> 
>  .def("CreateCross",CreateCross1)
>  .def("CreateCross",CreateCross2)
> 
>  The one I call as a bound method, and the other unbound, i.e.:
> 
>  Vector2 = Vector1.CreateCross(Vector3)
>  Vector2 = module.Vector.CreateCross(Vector1,Vector3)
> 
>  Is something going on here that I'm not seeing. They work ok apparently.

Both are calling CreateCross2.

>  Regarding the vector problem. I cannot modify the original C++ code.  I want to keep Norma
lize as
>  an unbound method in Vector since I might have name collisions if I
>  put them at the module level. 

What collisions?  There's overloading at the module level too, you
know.

>  I tried .def("Yahoo",Normalize3) but it too gave me a type
>  error. What is Boost trying to do? 

I have no idea; post a reproducible test case.

Maybe you forgot to make it static?

>  The function pointer is poiting to the correct function.
> 
>  Furthermore, don't you have to do something different than just a
>  plain .def since the arguments to Normalize are references? 

No.

>  Does Boost automatically detect this?

It does detect that they are references.

>  How does it deal with something like:
> 
>  Add(int x, int y, int &result)
> 
>  So when you do >>>Add(x,y,result) in python, what happens?

argument error, but that's because Python ints are immutable.  Classes
don't play by the same rules.

>  I think I'm missing something fundamental here... :(
> 
>  Thanks for your help.
>  Joel

Sure thing.

-- 
Dave Abrahams
Boost Consulting
www.boost-consulting.com


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