Victor Nakoryakov wrote:
>  Ok, I think my previous post was too complicated, here is simplified 
>  version:
>  
>  
> >class A
> >{
> >};
> >
> >boost::shared_ptr<A> ptr;
> >boost::shared_ptr<A> getA()
> >{
> >	if (!ptr)
> >		ptr = boost::shared_ptr<A>(new A);
> >
> >	return ptr;
> >}
> >
> >void Init()
> >{
> >	python::class_< A, boost::shared_ptr<A>, boost::noncopyable >( "AClass", python::no_init 
);
> >	python::def("getA", &getA);
> >}
>  
>  
>  And py code is:
>  
>  
> >a1 = getA()
> >a2 = getA()
> >l = [a1, a2]
> >print a1
> >print a2
> >print getA() in l
> >print a1 is a2
> >print a1 == a2
>  
>  
>  Output is:
>  
>  <_mymodule.AClass object at 0x017DB070>
>  <_mymodule.AClass object at 0x017DB0B0>  <- another address!
>  False
>  False
>  False
>  
>  The question is the same: What I have to do to have the same address of 
>  AClass every time I call getA() from python.
>  
>  I can't find solution already for 3 days. Have anyone ideas?
>  

Ok... The question is simplified. Who knows a chain that converts 
HeldType (boost::shared_ptr<A>  in this case) to PyObject* ? And where I 
can done any overloads or specializations to force c++ to return the 
same PyObject* for the same raw pointer to A instance?

I don't know is it question simplification, or vice versa, but anyway 
I'm in great need of an answer.

-- 
Victor (aka nail) Nakoryakov
nail-mail<at> mail<dot>ru

Krasnoznamensk, Moscow, Russia

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