On 13 Jul 2003 20:10:17 -0400
"Alan Grosskurth" <alan.grosskurth@[...].ca>  wrote:

>  That works fine for 8-bit images, but I'm
>  still have trouble with mode 'I' images (32-bit integer):
>  
>      image = Image.new('I', (10, 10))
>      out = Image.eval(image, math.sqrt)

This gets beyond my knowledge. That code calls point(), and according to
the docs:

    If the image has mode "I" (integer) or "F" (floating point), you
    must use a function, and it must have the following format: argument
    * scale+ offset 

    Example: Map floating point images 

        out = im.point(lambda i: i * 1.2 + 10) 

    You can leave out either the scale or the offset.

Using the example lambda works in your eval(), but I don't see how to
get in a sqrt(). Perhaps someone with better Python knowledge can help?

-Bill
-- 
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