Giorgio Luciano wrote:
>  Today  I've also posted a question to scipy groups because I've thought 
>  I've found a solution but
>  
>  this work good
>  
>  bar(N, b1[:,0], width, color='r', yerr=binterv)
>   ############
>   s3=find(sig1[:,arange(ini,c)]<=0.001)
>   b1=b.flatten()
>   #if s3!=[]:
>   for i3 in arange(len(s3)):
>    text(s3[i3], b1[s3[i3]+ini],'***')
>   s2=find(logical_and(sig1[:,arange(ini,c)]>0.001,sig1[:,arange(ini,c)]<=0.01))
>   for i2 in arange(len(s2)):
>    text(s2[i2], b1[s2[i2]+ini],'**')
>   s1=find(logical_and(sig1[:,arange(ini,c)]>0.01,sig1[:,arange(ini,c)]<=0.05))
>   for i1 in arange(len(s1)):
>    text(s1[i1], b1[s1[i1]+ini],'*')
>   title('Plot of the coefficients of the model')
>  
>  and when i uncomment the ifs3!=[] part it does not...
>  so in this case I've solve the problem.. but is there an equivalent for 
>  isempty matlab command in numpy ?

Use (len(s3) != 0) instead of (s3 != []).

-- 
Robert Kern

"I have come to believe that the whole world is an enigma, a harmless enigma
 that is made terrible by our own mad attempt to interpret it as though it had
 an underlying truth."
  -- Umberto Eco
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