& XSLT > >>>> "Randal" == Randal L Schwartz <merlyn@[...].com> writes:

A>  Thatâ??s missing an

A>  extension-element-prefixes="foo"

Randal>  Not according to the examples, and it works without it.

And now that I've stared at the O'Reilly XSLT book a bit, I can see what this
is used for.  Does XML::LibXSLT (and perhaps libxslt2) not provide the means
by which I can register *all* calls from a namespace to be mapped to a class?
Apparently, I must register each individual function instead.

Can I override XML::LibXSLT::perl_dispatcher somehow to do the delivery I
want, or will I not get called if I use "foo:unknown_function" in my
expression?  I see $func can be either a coderef or a package name there, but
it's still being mapped on a full Qname basis, not on a prefix basis.

-- 
Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095
<merlyn@[...].com>  <URL:http://www.stonehenge.com/merlyn/>
Perl/Unix/security consulting, Technical writing, Comedy, etc. etc.
See PerlTraining.Stonehenge.com for onsite and open-enrollment Perl training!

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