Re: parse a string (Cadence Allegro Netlist) to dictionary
by Joel Davis other posts by this author
Nov 6 2009 10:30PM messages near this date
Re: parse a string (Cadence Allegro Netlist) to dictionary
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Re: parse a string (Cadence Allegro Netlist) to dictionary
On Nov 5, 7:23 pm, metal <metal...@[...].com> wrote:
> On 11æ6æ¥, ä¸å4æ¶02å, Leland <lelandp...@[...].com> wrote:
>
>
>
> > Hi,
>
> > I always use readline(), strip(), split() and so on to parse a string.
> > Is there some elegant way to parse the following string into a
> > dictionary {'50MHZ_CLK_SRC' : 'U122.2, R1395.1'}?
>
> > NET_NAME
> > '50MHZ_CLK_SRC'
> > '@TEST_LIB.TEST(SCH_1):50MHZ_CLK_SRC':
> > C_SIGNAL='@test_lib.test(sch_1):\50mhz_clk_src\';
> > NODE_NAME U122 2
> > '@TEST_LIB.TEST(SCH_1):PAGE92_I223@INF_LOGIC.CY2305(CHIPS)':
> > 'CLK2': CDS_PINID='CLK2';
> > NODE_NAME R1395 1
> > '@TEST_LIB.TEST(SCH_1):PAGE92_I232@INF_RESISTORS.RESISTOR(CHIPS)':
> > 'A': CDS_PINID='A';
>
> > Thanks,
> > Leland
>
> not very elegantly too.
>
> x = re.findall("_NAME[\n\s']+((?<=').+(?=')|\w+\s+\w+)", s)
> """
> print {x[0]: x[1:]}>>> {'50MHZ_CLK_SRC': ['U122 2', 'R1395 1']}
>
> """
@metal
Apparently you and I differ considerably on our conceptions of
elegance.
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Thread:
Leland
Rhodri James
Joel Davis
Emile van Sebille
Metal
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