On Nov 7, 10:36 pm, Bruno Desthuilliers
<bdesth.quelquech...@[...].fr>  wrote:
>  asit a écrit :
> 
>  > In my program I want to catch exception which is caused by accessing
>  > NoneType object.
> 
>  > Can anyone suggest me how this can be done ??
> 
>  Not without the minimal working code exposing your problem, or the full
>  traceback you got. Merely "accessing NoneType object" doesn't by itself
>  raise any exception... I suspect you get the None object where you
>  expected something else and try to access an attribute of this
>  'something else', and ends up getting an AttributeError, but there are
>  other possible scenarii that might fit your (very poor) description of
>  the problem, so no way too help you without more informations. As a
>  general rule, remember that the traceback is actually meant to *help*
>  finding out what went wring.

I could have described the error, but the problem is that it's
dependent of a third party library..

Let me write the code here...

import twitter

api = twitter.Api('asitdhal','swordfish')
users = api.GetFriends()
for s in users:
    print
    print "##########################################"
    try:
        print "user id : " + str(s.id)
        print "user name : " + s.name
        print "user location : " + s.location
        print "user description : " + s.description
        print "user profile image url : " + s.profile_image_url
        print "user url : " + s.url
        print "user status : " + str(s.status)
    except TypeError:
        pass


look at the except TypeError. This is supposed to catch only exception
thrown by NoneType.

please help me.
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