The Python-Card guys are really helpful, <
pythoncard-users@[...].net> , you may have to register on
sourceforge to get on their list.

In the meantime I went ahead and cc'd them on this. Python-Card guys, make
sure to cc Steven as he may not be on the list.

-Greg


On 10/7/05, Steven D'Aprano <steve@[...].au>  wrote:
> 
>  On Fri, 07 Oct 2005 10:25:24 -0700, jlocc wrote:
> 
>  > Hi!!
>  >
>  > I am working on a school project and I decided to use PythonCard and
>  > wxPython for my GUI development. I need a password window that will
>  > block unwanted users from the system. I got the pop-up password
>  > question to work...
> 
>  I haven't seen any replies to this, so even though I don't actually
>  use Pythoncard I'll take a wild shot in the dark.
> 
> 
>  > def on_openBackground(self, event):
>  >
>  > result = dialog.textEntryDialog(self,
>  > 'System',
>  > 'Please enter your password: ',
>  > '')
>  >
>  > .....but I don't exactly remember how to check if the entered password
>  > is correct. Say I hard code the password to be 'hello', then how would I
>  > check if this was the input or if it wasn't???
> 
>  Start with looking at result and seeing what is in it. If it is the input
>  string, then just say
> 
>  if result == 'hello':
>  # do whatever you need to
>  else:
>  # put up a dialog saying 'Password does not match!'
> 
>  But I'm guessing from the syntax that the dialog instance itself is stored
>  in result, so perhaps you need to look at some attribute of result:
> 
>  if result.userInput == "hello": # or something like that?
> 
>  Lastly, I might not have used Pythoncard, but years ago I used to use
>  Hypercard rather a lot. In Hypercard, the password dialog would use a
>  one-way hash function to encrypt the typed response into a large integer
>  value. I assume Pythoncard is designed to do the same thing as Hypercard.
> 
>  So, in rusty Hypercard syntax with Python-style comments:
> 
>  # retrieve the numeric value of the password
>  put field "hidden password" into userpassword
>  # put up a dialog asking the user to enter a password
>  ask password "Please enter your password:"
>  if the result is "" then:
>  # the user clicked Cancel, so just abort or go away or something
>  go home
>  else if the result is userpassword:
>  # we have a match!
>  go to card "Secret card"
>  else:
>  # password doesn't match
>  go to card "Password failure"
> 
> 
>  Hope this is of some help to you, and I haven't led you too far astray.
> 
> 
>  --
>  Steven.
> 
>  --
>  http://mail.python.org/mailman/listinfo/python-list
> 



--
Gregory Pi�ero
Chief Innovation Officer
Blended Technologies
(www.blendedtechnologies.com <http://www.blendedtechnologies.com> )