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I had written a few days ago about getting this error when I try to run
the latest macho_standalone on an app bundle in this fashion:

macho_standalone ~/Desktop/Myapp.app:

  File
"/Library/Frameworks/Python.framework/Versions/Current/bin/macho_standalone",
line 20, in ?
    main()
  File
"/Library/Frameworks/Python.framework/Versions/Current/bin/macho_standalone",
line 17, in main
    standaloneApp(fn)
  File
"/Library/Frameworks/Python.framework/Versions/Current/bin/macho_standalone",
line 10, in standaloneApp
    files = MachOStandalone(path).run()
TypeError: __init__() takes at least 3 arguments (2 given)


Digging a bit deeper into the macholib code, I noted that
MachOStandalone.py calls for an "archs" argument:

class MachOStandalone(object):
    def __init__(self, base, archs, dest=None, graph=None, env=None,
executable_path=None):
        self.base = os.path.join(os.path.abspath(base), '')
        if dest is None:
            dest = os.path.join(self.base, 'Contents', 'Frameworks')
        self.dest = dest
        self.mms = dict([[arch, FilteredMachOGraph(self, arch,
graph=graph, env=env, executable_path=executable_path)] for arch in archs])
        self.changemap = {}
        self.excludes = []
        self.pending = deque()
        self.archs = archs


So what I'm trying to figure out is how to correctly pass the "archs"
argument in my command-line parameters. I've tried four variants:

macho_standalone ~/Desktop/Myapp.app ppc
macho_standalone ~/Desktop/Myapp.app "archs = 'ppc'"
macho_standalone ~/Desktop/Myapp.app "archs = ['ppc']"
macho_standalone ~/Desktop/Myapp.app -archs ppc

All of these yield the same error message as above.

I think I'm on the right track here, because when I hard-code the ppc
architecture in the __init__ def above, macho_standalone works.

   def __init__(self, base, archs=['ppc'], dest=None, graph=None,
env=None, executable_path=None):

So what I need to do is find the correct magic to get the command-line
args invoked properly. Does anyone have any suggestions?

Thanks!


- --
Kevin Walzer
Poetic Code
http://www.kevin-walzer.com
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