Re: Doing an AND in regexp char class
by David A. Black other posts by this author
May 8 2008 6:04PM messages near this date
Re: Doing an AND in regexp char class
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Re: Doing an AND in regexp char class
Hi --
On Fri, 9 May 2008, Joel VanderWerf wrote:
> David A. Black wrote:
> >> irb(main):013:0> /(?=.*h)(?=.*o)/ === "h o"
> >> => true
> >
> > That depends on the order, though.
>
> Yes, it's buggy. Should use //m:
>
> irb(main):003:0> /(?=.*h)(?=.*o)/ === "o \nh"
> => false
> irb(main):004:0> /(?=.*h)(?=.*o)/m === "o \nh"
> => true
>
> Does that fix the order problem you were thinking of?
Actually I think I was wrong about the order mattering (since they're
zero-width). But /m helps anyway. I still think you could just change
the roles of the two strings and dissect "the string" as a character
class and "the characters" as a string, and use your original
technique.
David
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