Re: Doing an AND in regexp char class
by David A. Black other posts by this author
May 9 2008 1:57AM messages near this date
Re: Doing an AND in regexp char class
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Re: Doing an AND in regexp char class
Hi --
On Fri, 9 May 2008, 7stud -- wrote:
> Joel VanderWerf wrote:
> > Todd Benson wrote:
> >>>>
> >>>> Thanks,
> >>> p 'foobar'.all_chars?('')
> >>>
> >>>
> >>>
> >>> cfp:~ > ruby a.rb
> >>> true
> >>> false
> >>> false
> >>
> >> Cool :) #tr is one of those useful methods I somehow consistently forget about.
> >
> > But it can be done with regex, right? It's just more elegant with tr.
> >
> > class String
> > def all_chars? chars
> > if chars.empty?
> > empty?
> > else
> > /\A[#{chars}]*\z/ === self
> > end
> > end
> > end
> >
> > p 'foobar'.all_chars?('rabof') # => true
> > p 'foobar'.all_chars?('abc') # => false
> > p 'foobar'.all_chars?('') # => false
>
> Your method doesn't work, which can clearly be seen in these examples:
>
> strs = ["aaa", "bbb", "ccc"]
> chars = "abc"
>
> strs.each do |str|
>
> if /\A[#{chars}]*/ =~ str
> print str, " - yes"
> puts
> else
> print str, " - no"
> puts
> end
>
> end
>
> --output:--
> aaa - yes
> bbb - yes
> ccc - yes
>
> It should be clear from the output that even though the string "aaa"
> passes your test, it is not true that all the characters in the string
> "abc" appear in in the string "aaa".
Do it the other way around (and don't forget the \z):
if /\A[#{str}]*\z/ =~ chars
It's really the characters in str that you're testing, to make sure
that none of them fail to match the characters in chars. If the
variable names seem backwards, you can change them. It's the logic
that's important, and it works fine.
David
--
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Thread:
Todd Benson
Rick DeNatale
Ara.T.Howard
Pit Capitain
Todd Benson
Joel VanderWerf
7stud --
David A. Black
7stud --
Todd Benson
David A. Black
Joel VanderWerf
Todd Benson
David A. Black
Joel VanderWerf
David A. Black
Ara.T.Howard
Robert Dober
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