FAQ,

>  In the next xsl I want to make that the param "cod" be 
>  incremented in each time that the <xsl:for-each> cicle 
>  occurs, but it's result is an error:
>  
>  "javax.xml.transform.TransformerException: xsl:with-param is 
>  not allowed in this position in the stylesheet!"
>  
>  Why?!
>  Tks
>  
>  <?xml version="1.0" encoding="ISO-8859-1"?>
>  <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>      version="1.0"
>      xmlns:xalan="http://xml.apache.org/xslt">
>  	<xsl:param name="cod">0</xsl:param>
>  	<xsl:output method="html"/>
>  	<xsl:template match="/">
>      		<xsl:for-each select=".//Boy">
>      			<xsl:with-param name="cod" 
>  select="number($cod+1)"/>
>  			<!--make other things-->
>  		</xsl:for-each>
>  	</xsl:template>
>  </xsl:transform>

XSLT doesn't allow you to update parameter values after they've been bound. Repeat "recursio
n is my friend" ten times, and you'll get the hang of it.

Anyhow, rewrite your stylesheet to

  <xsl:param name="cod" select="0" /> 
  <xsl:template match="/"> 
    <xsl:for-each select="//Boy"> 
      <xsl:variable name="_cod" select="$cod + position()" /> 
	<!--make other things--> 
    </xsl:for-each> 
  </xsl:template> 

And use $_cod instead of $cod in "make other things". Use select attribute in the xsl:param 
to bind the parameter into a number, instead of a RTF <http://www.w3.org/TR/xslt#section-Res
ult-Tree-Fragments> .

Cheers,

Jarno

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