Write an identity template rule that copies elements:

<xsl:template match="*"> 
<xsl:copy> 
<xsl:copy-of select="@*"/> 
<xsl:apply-templates/> 
</xsl:copy> 
</xsl:template> 

And an empty template rule that skips the others:

<xsl:template match="V|U"/> 

Michael Kay

>  -----Original Message-----
>  From: owner-xsl-list@[...].com 
>  [mailto:owner-xsl-list@[...].com] On Behalf Of 
>  poppe chris
>  Sent: 31 October 2003 12:20
>  To: XSL-List@[...].com
>  Subject: [xsl] Xml to Xml
>  
>  
>  
>  
>  Hello i want to converse an xml doc to an other one but 
>  leaving out some 
>  elements, ive tried several ways but it just wont work,
>  
>  here's what the original xml looks like
>  <?xml version="1.0"?>
>  <Bitstream xml:base="../CONTENT/final.yuv" 
>  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="YUV" 
>  xmlns:yuv="YUV" xsi:schemaLocation="YUV 
>  file:/D:/school/DIA-BSDL-1%5B1%5D.1/DELIVERY_2003_08_13/BSDLSo
urce/../CONTENT/SCHEMAS/YUV.xsd"> 
	<Frame> 
		<Y> 
			<Ysample> 0 811008</Ysample>
		</Y> 
		<V> 
			<Vsample> 811008 405504</Vsample>
		</V> 
		<U> 
			<Usample> 1216512 405504</Usample>
		</U> 
	</Frame> 
	<Frame> 
		<Y> 
			<Ysample> 1622016 811008</Ysample>
		</Y> 
		<V> 
			<Vsample> 2433024 405504</Vsample>
		</V> 
		<U> 
			<Usample> 2838528 405504</Usample>
		</U> 
	</Frame> 
</Bitstream> 

now i want the same but withouth the V and U elements and their children

thus something like
<Bitstream ...> 
  <Frame> 
     <Y>    <Ysample>...</Ysample></Y>
  </Frame> 
  ...
</Bitstream> 

thanks in advance,
Chris

_________________________________________________________________
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