Hi,
  Thanks for the people who posted and answered this question. This gives me lead to solve s
ome other problem. 
But I have a slightly different problem though.

My XML is like:
<root> 
	<foo> 
    		<bar> Cust1 443 West</bar>
    		<bar2> Cust1</bar2>
	</foo> 
	<foo> 
    		<bar> Cust1 443 East</bar>
    		<bar2> Cust1</bar2>
	</foo> 
	<foo>  
    		<bar> Cust1 443 East</bar>
    		<bar2> Cust1</bar2>
	</foo> 
	<foo> 
    		<bar> Cust1 443 West</bar>
    		<bar2> Cust1</bar2>
	</foo> 
</root> 
 and I want my output to be something like

Cust1 443 West
Cust1 443 East

and I tried with 


<xsl:for-each select="root[not(foo/bar = preceding-sibling::foo/bar)]"> 

    <xsl:value-of select="."/> <br/>

</xsl:for-each> 

but, it doesn't seem like working. 

Any help with this??
thanks.

~Mur





Heres a quick fix to your grouping problem...

If the XML was in the following format...

<foo> 
    <bar> Cust1 443 West</bar>
    <bar> Cust1 443 West</bar>
    <bar> Cust1 443 West</bar>
    <bar> Cust1 443 East</bar>
</foo> 

the following XSL will test to see if the current node is equal to any of
the preceding elements and if it is it will not include it in the resulting
node-set.  It then prints the value of each node.  So this...

<xsl:for-each select="foo/bar[not(. = preceding-sibling::bar)]"> 

    <xsl:value-of select="."/> <br/>

</xsl:for-each> 

Will produce this...

Cust1 443 West
Cust1 443 East

Best of luck,

M.


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list