That doesn't work since the context node isn't the node for the for-each.

This is the complete for-each:

<xsl:for-each select="ROW[count(. | key('tipos', D)[1]) = 1]"> 
  a_valores[<xsl:value-of select="position()-1" /> ] = new Array(<xsl:value-of select="count(
. | key('tipos', A)[1])" /> );      
  a_valores[<xsl:value-of select="position()-1" /> ][<xsl:value-of select="count(. | key('tip
os', D))-1" /> ] = new Array(2);
  a_valores[<xsl:value-of select="position()-1" /> ][<xsl:value-of select="count(. | key('tip
os', D))-1" /> ][0] = <xsl:value-of select="D" />;
  a_valores[<xsl:value-of select="position()-1" /> ][<xsl:value-of select="count(. | key('tip
os', D))-1" /> ][1] = <xsl:value-of select="D" />;  
</xsl:for-each> 

This follows the muenchian grouping algorithm. In that case position() gets the parent of RO
W since the template is:
<xsl:template match="ficha_tecnica/ROWSET"> 

The way I have now is by using count(. | key('tipos', D)) and it works, but I think that if 
I have more data, that process will be inefficient since it has to count the actual nodes fo
r each iteration.

My for-each gets the following:

a_valores[0] = new Array(1);      
a_valores[0][0] = new Array(2);
a_valores[0][0][0] = .30726074;
a_valores[0][0][1] = .30726074;  
      
a_valores[1] = new Array(1);      
a_valores[1][0] = new Array(2);
a_valores[1][0][0] = .12244368;
a_valores[1][0][1] = .12244368;  
      
a_valores[2] = new Array(1);      
a_valores[2][0] = new Array(2);
a_valores[2][0][0] = .4071683;
a_valores[2][0][1] = .4071683;  


Jaime

>  -----Mensaje original-----
>  De: owner-xsl-list@[...].com
>  [mailto:owner-xsl-list@[...].com]En nombre de David
>  Carlisle
>  Enviado el: Jueves, 11 de Diciembre de 2003 12:32
>  Para: xsl-list@[...].com
>  Asunto: Re: [xsl] getting the counter for a for-each statement
>  
>  
>  
>  this has already been answered today in a differentthread.
>  <xsl:value-of select="position()"/>
>  
>  
>  
>  -- 
>  http://www.dcarlisle.demon.co.uk/matthew
>  
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