& XSLT The value of (df_data/@column = $sort) is a boolean, true or false. So your
sorted sequence will contain all the values for which the content of the
@column attribute is not equal to the value of the variable $sort, followed
by those for which it is equal.

I don't like these XML documents in which the elements are called "row" and
"column". My instinct would be to first transform it to a document that uses
application-oriented tags, for example

<person> 
  <name> Value</name>
  <phone> Value2</phone>
</person> 

and then use that as the input to your "real" transformation.

But if you need to, the answer to your question is
sort="df_data[@column=$sort]".

And it should be order="{$dir}".

Michael Kay
http://www.saxonica.com/

>  -----Original Message-----
>  From: Adam J Knight [mailto:adam@[...].au] 
>  Sent: 18 April 2005 01:29
>  To: xsl-list@[...].com
>  Subject: [xsl] xsl sort: using element attribute as sort key!
>  
>  Hi all, 
>  
>  I am trying to sort based on an elements attribute. Doesn't 
>  seem to work.
>  Can i do this, and if so, what am i doing wrong? 
>  Replies greatly appreciated!
>  
>  $sort parameter = 'name'
>  $dir parameter = 'descending'
>  
>  xml structure:
>  <dfile>
>    <df_data_row>
>      <df_data column='name'>Value</df_data>
>    </df_data_row>
>    <df_data_row>
>      <df_data column='phone'>Value2</df_data>
>    </df_data_row>
>  </dfile>
>  
>  <xsl:if test="$sort">
>    <xsl:apply-templates select="dfile/df_data_row">
>      <xsl:sort select="df_data/@column = $sort" 
>  order="$dir"></xsl:sort>
>    </xsl:apply-templates>  
>  </xsl:if>
>  
>  Cheers, 
>  Adam 
>   
>  
>  
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