& XSLT You should do this as a pipelined (or multi-phase) transformation. Put the
results of the first grouping/sorting operation in a variable (a temporary
tree) and then apply another transformation to put the elements into groups
of three.

Michael Kay
http://www.saxonica.com/
 

>  -----Original Message-----
>  From: beowulf [mailto:carisenda@[...].com] 
>  Sent: 18 April 2005 11:12
>  To: xsl-list@[...].com
>  Subject: [xsl] grouping, sorting, splitting
>  
>  Hi,
>  
>  I have XML if the form:
>  
>  <page>
>  <entry date="2005-04-15">
>   <title>foo</title>
>  </entry>
>  <entry date="2005-04-15">
>   <title>bar</title>
>  </entry>
>  <entry date="2005-02-05">
>   <title>baz</title>
>  </entry>
>  ...
>  </page>
>  
>  Which I am trying to group by date, sort by tiltle and then split into
>  sets of 3, 3 being the number of columns in the HTML TABLE element I
>  am trying to produce as an end result.
>  
>  I've got the grouping and sorting:
>  <xsl:for-each select="entry[key('days', @date) and count(.|key('days',
>  @date)[1])= 1]">
>  <xsl:sort select="title"/>
>  
>  and I've even got the first item in each group of three from that
>  grouped and sorted set:
>  <xsl:for-each select="key('days', @date)[position() mod 3 = 1]">
>  
>  But I just can't seem to make the final leap to displaying the
>  following siblings of the above, making the 3 cell rows. Should I be
>  doing this some other way or can someone help me where I am?
>  
>  Many thanks,
>  Stephen
>  
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