Re: [xsl] grouping, sorting, splitting
by Mukul Gandhi other posts by this author
Apr 18 2005 4:39AM messages near this date
RE: RE: RE: RE: RE: [xsl] GMT to BST converter
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Re: [xsl] grouping, sorting, splitting
& XSLT Hi Stephen,
Please try this XSL..
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html" indent="yes" />
<xsl:key name="by-date" match="entry" use="@date" />
<xsl:template match="/page">
<html>
<head>
<title/>
</head>
<body>
<table>
<xsl:for-each select="entry[generate-id() =
generate-id(key('by-date', @date)[1])]">
<xsl:for-each select="key('by-date',
@date)">
<xsl:sort select="title" />
<xsl:if test="(position() = 1) or
((position() - 1) mod 3 = 0)">
<xsl:variable name="pos"
select="position()" />
<tr>
<xsl:call-template
name="generateTRs">
<xsl:with-param name="node-set"
select="key('by-date', @date)[position() >=
$pos][position() <= ($pos + 3)]" />
</xsl:call-template>
</tr>
</xsl:if>
</xsl:for-each>
<!-- a dummy row -->
<tr>
<td> -</td><td>-</td><td>-</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
<xsl:template name="generateTRs">
<xsl:param name="node-set" />
<tr>
<xsl:for-each select="$node-set">
<td>
<xsl:value-of select="@date" />
</td>
</xsl:for-each>
<xsl:call-template name="generateRemainingTDs">
<xsl:with-param name="n" select="3 -
count($node-set)" />
</xsl:call-template>
</tr>
</xsl:template>
<xsl:template name="generateRemainingTDs">
<xsl:param name="n" />
<xsl:if test="$n > 0">
<td/>
<xsl:call-template name="generateRemainingTDs">
<xsl:with-param name="n" select="$n - 1" />
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- beowulf <carisenda@[...].com> wrote:
> Hi,
>
> I have XML if the form:
>
> <page>
> <entry date="2005-04-15">
> <title>foo</title>
> </entry>
> <entry date="2005-04-15">
> <title>bar</title>
> </entry>
> <entry date="2005-02-05">
> <title>baz</title>
> </entry>
> ...
> </page>
>
> Which I am trying to group by date, sort by tiltle
> and then split into
> sets of 3, 3 being the number of columns in the HTML
> TABLE element I
> am trying to produce as an end result.
>
> I've got the grouping and sorting:
> <xsl:for-each select="entry[key('days', @date) and
> count(.|key('days',
> @date)[1])= 1]">
> <xsl:sort select="title"/>
>
> and I've even got the first item in each group of
> three from that
> grouped and sorted set:
> <xsl:for-each select="key('days', @date)[position()
> mod 3 = 1]">
>
> But I just can't seem to make the final leap to
> displaying the
> following siblings of the above, making the 3 cell
> rows. Should I be
> doing this some other way or can someone help me
> where I am?
>
> Many thanks,
> Stephen
>
>
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Thread:
Mukul Gandhi
Mukul Gandhi
Mukul Gandhi
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