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MyASPN >> Mail Archive >> xsl-list
xsl-list
[xsl] Splitting already-grouped output into two parts
by Asparagirl other posts by this author
Dec 27 2005 11:19AM messages near this date
RE: [xsl] removing namespace | RE: [xsl] Splitting already-grouped output into two parts
& XSLT Hi.  I'm having problems with XSLT and was hoping someone here could help me
troubleshoot or offer advice.  

Here's a sample of my XML (edited to remove superfluous stuff):

============================================
<RECORDS> 
<RECORD> 
      <name> Anderson, Bob</name>
      <AssetID> 1426419</AssetID>
</RECORD> 
<RECORD> 
      <name> Anderson, Bob</name>
      <AssetID> 1440105</AssetID>
</RECORD> 
<RECORD> 
      <name> Brock, Jessica</name>
      <AssetID> 1429062</AssetID>
</RECORD> 
<RECORD> 
      <name> Carlisle, Jen</name>
      <AssetID> 1426278</AssetID>
</RECORD> 
<RECORD> 
      <name> Carlisle, Jen</name>
      <AssetID> 1436229</AssetID>
</RECORD> 
<RECORDS> 
============================================

I'm using the Muenchian Method to group my results by surname.  Here's my
stylesheet (again, edited to remove lots of superfluous stuff):

============================================
<xsl:key name="videos-by-surname" match="RECORD" use="name" /> 

<xsl:template match="RECORDS"> 
<xsl:for-each select="RECORD[count(. | key('videos-by-surname', name)[1]) = 1]"> 

<xsl:sort select="name" /> 
<xsl:element name="h3"> <xsl:value-of select="name" />:</xsl:element>
<xsl:element name="ul"> 
   <xsl:for-each select="key('videos-by-surname', name)"> 
      <xsl:sort select="AssetID" /> 
      <xsl:element name="li"> <xsl:value-of select="AssetID" /></xsl:element>
   </xsl:for-each> 
</xsl:element> 

</xsl:for-each> 
</xsl:template> 
============================================

So far, it all works fine; the output looks sort of like this:

============================================
<h3> Anderson, Bob:</h3>
<ul> 
  <li> 1426419</li>
  <li> 1440105</li>
</ul> 

<h3> Brock, Jessica:</h3>
<ul> 
   <li> 1429062</li>
</ul> 

<h3> Carlisle, Jen:</h3>
<ul> 
   <li> 1426278</li>
   <li> 1436229</li>
</ul> 
============================================

But what I'd like to do is take this grouped output and divide it into two
roughly-equally sized groups.  That is, I'd like to create two DIV's, each
with about half the data in them.  I do not want to use tables.  And I don't
want to break up the UL's/LI's across the columns; each of the tops of the
columns need to start with a new H3 name and its associated grouping, not be
continued from the previous column.

So, how can I count up all the resulting H3's/names from my Muenchian
grouping, divide it by two, and then wrap each of the two new groups in
DIV's?  It's likely something simple, but I'm flummoxed.  Please help a
fuzzy newbie!  (Explanations using small words would be much appreciated.)

Thanks!


- Brooke Schreier Ganz

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Thread:
Asparagirl
cknell
Thomas Maciejewski
Asparagirl

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