getattr(context.aq_explicit,'nickname',None)

cheers,

Chris

dave@[...].com wrote:
>  
>  I'm building a python script to generate breadcrumb navigation links on 
>  each page of my website.
>  
>  It creates hyperlinks and uses the title or id for the link. I'd like to 
>  add a feature so that if the folder has a "nickname" property, it will 
>  use this for the breadcrumb hyperlink instead of the title.
>  
>  I tried using "hasattr()" to see if the current folder has a nickname 
>  property. It seems to work if the folder has a nickname property. 
>  However, if the folder doesn't have that properly, but the parent does, 
>  it still returns "true" and then getattr() acquires it from the parent 
>  instead of using the title. Is there a way to tell hasattr() to *not* 
>  use acquisition? Or perhaps another method which would do what I want? 
>  I'm sure there is a much more elegant way to do this...
>  
>  (These question feels like a FAQ, and I did do my best to search the 
>  group archives, but couldn't find anything appropriate-- most breadcrumb 
>  conversations seem to revolve around DTML and getProperty().)
>  
>  --dave
>  
>  
>  """
>  This script creates breadcrumb style navigation links.
>  
>  It walks the REQUEST.PARENTS list of parents and creates
>  a hyperlink for each parent. It stops at the Examples folder.
>  """
>  links=[]
>  for parent in context.REQUEST.PARENTS[1:]:
>      id = parent.getId()
>      if hasattr(parent, 'nickname'):
>          label = getattr(parent, 'nickname')
>      elif parent.title != "":
>          label = parent.title
>      else:
>          label = parent.getId()
>      links.insert(0, """<a href="%s" class="breadcrumb">%s</a>""" % 
>  (parent.absolute_url(), label))
>  
>  # Now get label for current container
>  if context.hasProperty('nickname'):
>    label = context.nickname
>  elif context.title != "":
>    label = context.title
>  else:
>    label = context.getId()
>  
>  return " : ".join(links) + " : " + label



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